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A string literal `"abc"` contains a terminating `\0`, so that is 4 bytes. There is no need to write `"abc\0"` unless two terminating `\0`s are necessary. `std::string` objects do not internally contain a terminating `\0`, so `std::string("abc")` creates a string with size 3 and is the same as `std::string("abc", 3)`. In `"\01"` the `01` part is interpreted as one number (1) and that is the same as `"\1"` which is a string like `{1, 0}` whereas `"\0z"` is a string like `{0, 'z', 0}`. To create a string like `{0, '1', 0}` one must use `"\0" "1"`. Adjust the tests accordingly.
39 lines
1.3 KiB
C++
39 lines
1.3 KiB
C++
// Copyright (c) 2011-2020 The Bitcoin Core developers
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// Distributed under the MIT software license, see the accompanying
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// file COPYING or http://www.opensource.org/licenses/mit-license.php.
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#include <test/util/setup_common.h>
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#include <util/strencodings.h>
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#include <boost/test/unit_test.hpp>
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#include <string>
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using namespace std::literals;
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BOOST_FIXTURE_TEST_SUITE(base64_tests, BasicTestingSetup)
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BOOST_AUTO_TEST_CASE(base64_testvectors)
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{
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static const std::string vstrIn[] = {"","f","fo","foo","foob","fooba","foobar"};
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static const std::string vstrOut[] = {"","Zg==","Zm8=","Zm9v","Zm9vYg==","Zm9vYmE=","Zm9vYmFy"};
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for (unsigned int i=0; i<sizeof(vstrIn)/sizeof(vstrIn[0]); i++)
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{
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std::string strEnc = EncodeBase64(vstrIn[i]);
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BOOST_CHECK_EQUAL(strEnc, vstrOut[i]);
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std::string strDec = DecodeBase64(strEnc);
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BOOST_CHECK_EQUAL(strDec, vstrIn[i]);
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}
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// Decoding strings with embedded NUL characters should fail
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bool failure;
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(void)DecodeBase64("invalid\0"s, &failure);
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BOOST_CHECK(failure);
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(void)DecodeBase64("nQB/pZw="s, &failure);
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BOOST_CHECK(!failure);
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(void)DecodeBase64("nQB/pZw=\0invalid"s, &failure);
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BOOST_CHECK(failure);
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(void)DecodeBase64("nQB/pZw=invalid\0"s, &failure);
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BOOST_CHECK(failure);
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}
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BOOST_AUTO_TEST_SUITE_END()
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