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refactor: Simplify SpanPopBack
Use the equivalent back() and first() member functions.
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1 changed files with 2 additions and 3 deletions
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@ -248,9 +248,8 @@ template <typename T>
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T& SpanPopBack(Span<T>& span)
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T& SpanPopBack(Span<T>& span)
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{
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{
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size_t size = span.size();
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size_t size = span.size();
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ASSERT_IF_DEBUG(size > 0);
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T& back = span.back();
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T& back = span[size - 1];
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span = span.first(size - 1);
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span = Span<T>(span.data(), size - 1);
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return back;
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return back;
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}
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}
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